Thursday 21st of November 06:34:43pm
Thursday 21st of November 06:34:43pm
Define an array, data, with 100 elements of type double. Write a loop that will
store the following sequence of values in corresponding elements of the array:
1/(2*3*4) 1/(4*5*6) 1/(6*7*8) ... up to 1/(200*201*202) Write another loop that
will calculate the following: data[0]-data[1]+data[2]-data[3]+... -data[99] Multiply
the result of this by 4.0, add 3.0, and output the final result. Do you recognize the
value that you get?
Solution:
#include<stdio.h>
int main()
{
int i;
double data[100];
double sum=0.0;
double sign=1.0;
for(i=1; i<=100; i++)
{
data[i-1]=1.0/(2*i*(2*i+1)*(2*i+2));
}
for(i=0; i<100; i++)
{
sum += sign*data[i];
sign=-sign;
}
printf("The result is %lf ",4.0*sum+3);
printf(" I Reconize this num this is pi num ");
}
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